Re: Tire Changing questions

[Jack Bunce <jackbunce@xxxxxxx>]

What does a rear wheel, tire, brake disk, and other miscellaneous parts 
weigh?

If the answer is at least 10 lbs that is equivalent to about 4,536 
grams. If that was off center by 0.001 inch that would be equivalent to 
exerting a torque of 4.5 gram/inches which out at the inside of the rim 
might be (4.5/15) or 0.3 grams out of balance at the rim.  Don't think 
you would notice that?

But that said, I agree that every effort must be made to fit the wheel 
properly to the balancing device. Allowing any slop would be self 
defeating!

For the BMW content: When I put my R1100SA on the centerstand and spin 
the rear wheel under power the bike feels unbalanced and shakes. Yet, I 
do not feel this imbalance on the road. Should I have the rear wheel 
pulled and balanced or is it normal for an R100SA to act that way on 
the centerstand with the rear wheel under power? [This came up because 
I had the bike on the dyno and the tester mentioned the rear wheel hop 
to me.  So I tried it at home.]


On Jun 22, 2004, at 4:47 AM, oilheads-digest wrote:

> Date: Mon, 21 Jun 2004 21:29:08 -0400
> From: PLPKLT@xxxxxxx
> Subject: Re: Tire Changing questions
>
> In a message dated 6/21/2004 10:24:51 AM Eastern Daylight Time, 
> cliddell@xxxxxxxxxx writes:
>
>> If you are a only a couple of thou's out then the whole
>> weight of the wheel acting at that tiny distance can easily equate to 
>> around
>> 10 or 20 g - and, of course, you are only un-balancing the
>> wheel :(
>
>
> I'd like to see you provide some calculations on that!   1/1000 of an 
> inch times 1 gram  = 10 or 20 G ( does this stand of Gravity or 
> something else....
>
> Jess with such obvious dangerious physics just waiting to jump on our 
> poor unbalanced wheels , it is a wonder were not all laying somewhere 
> in a ditch....
>
>
> Paige

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